Write a function that determines whether or not a list of values is in sorted order (either ascending or descending). The function should return True if the list is already sorted. Otherwise it should return False. Write a main program that reads a list of numbers from the user and then uses your function to report whether or not the list is sorted.
Hint:
Make sure you consider these questions when completing this exercise: Is a list that is empty in sorted order? What about a list containing one element?
#With this solution we assume that both an empty list and a list with one item are sorted def is_sorted(list_of_numbers): if sorted(list_of_numbers) == list_of_numbers: return True #Ok, not sorted ascending, lets check descending elif sorted(list_of_numbers, key=int, reverse=True) == list_of_numbers: return True #At this point we know it is not sorted return False def main(): list_of_numbers = [] #We use this boolean to indicate that we are not done done = False while not done: number = int(input("Enter a number. Exit with 0: ")) if number != 0: list_of_numbers.append(number) else: done = True print(is_sorted(list_of_numbers)) if __name__ == '__main__': main()